70t^2+140t-110=0

Solution for 70t^2+140t-110=0 equation:

70t^2+140t-110=0

a = 70; b = 140; c = -110;
Δ = b2-4ac
Δ = 1402-4·70·(-110)
Δ = 50400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50400}=\sqrt{3600*14}=\sqrt{3600}*\sqrt{14}=60\sqrt{14}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-60\sqrt{14}}{2*70}=\frac{-140-60\sqrt{14}}{140}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+60\sqrt{14}}{2*70}=\frac{-140+60\sqrt{14}}{140}
$